Advertisements
Advertisements
Question
Let x be the greatest number of 4 digits, which when divided by 15, 20 and 28 leaves in each case the remainder 2. The sum of digits of x is
Options
19
21
23
25
Advertisements
Solution
23
Explanation:
L.C.M. of 15, 20 and 28
= 2 × 2 × 5 × 3 × 7
= 420
Greatest 4 digit number = 9999.
The greatest 4 digit number is divisible by 420 = 9660.
The remainder in each case = 2.
Required number = 9660 + 2 = 9662.
Sum of digits = 9 + 6 + 6 + 2 = 23.
APPEARS IN
RELATED QUESTIONS
Difference between two numbers is 9 and difference between their squares is 981. Lowest of the two numbers is:
If z = 5 + 3i then the value of |z - 2| will be:
Which one is rational number ?
A polynomial of degree ‘3’ is called
A polynomial of degree ‘1’ is called
One-third of one-fourth of a number is 12. Then the number is
Sum of first 15 multiples of 8 is:
Reema, Ruchi, and Richa can make a painting in 15, 20 and 30 days, respectively. They undertake to make a painting for ₹ 810. The share of Reema exceeds that of Ruchi by
Three numbers are in the ratio of 3:4:5 and their LCM is 2400. Then, their HCF is
A red light flashes 3 times per minute and a green light flashes 5 times in two minutes at regular intervals. If both the lights start flashing at the same time, how many times do they flash together in each hour?
