Advertisements
Advertisements
Question
Let x be the greatest number of 4 digits, which when divided by 15, 20 and 28 leaves in each case the remainder 2. The sum of digits of x is
Options
19
21
23
25
Advertisements
Solution
23
Explanation:
L.C.M. of 15, 20 and 28
= 2 × 2 × 5 × 3 × 7
= 420
Greatest 4 digit number = 9999.
The greatest 4 digit number is divisible by 420 = 9660.
The remainder in each case = 2.
Required number = 9660 + 2 = 9662.
Sum of digits = 9 + 6 + 6 + 2 = 23.
APPEARS IN
RELATED QUESTIONS
The smallest number that should be subtracted from 2085, so that the new number is completely divisible by 23 is
If y = sec-1 `("x+1"/"x - 1") + "sin"^-1 ("x - 1"/"x + 1") "then" "dy"/"dx"` is equal to:
The differential coefficient of sin-1 `((1-"x"^2)/(1+"x"^2))` w.r.t. x is:
If the lines x + y = 1, 2x – y = 0 and x + 2y +λλ is equal to:
A rational fraction `("N"("x"))/("D"("x"))`, with D(x) not equal to zero and degree of N(x) is less than degree of D(x) is known as
Find the least number that when divided by 16, 18, and 20 leaves a remainder 4 in each case, but is completely divisible by 7.
If the numbers from 1 to 24, which are divisible by 2 are arranged in descending order, which number will be at 8th place from the bottom?
In a school of 500 students, 102 students can read Hindi and Tamil both, 200 students can read only Hindi. The students who can read only Tamil are:
If n = 1 + x, where x is the product of four consecutive positive integers, then which of the following is true?
II. n is a prime number
III. n is a perfect square
IV. n is odd number
