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Question
Let x be the greatest number of 4 digits, which when divided by 15, 20 and 28 leaves in each case the remainder 2. The sum of digits of x is
Options
19
21
23
25
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Solution
23
Explanation:
L.C.M. of 15, 20 and 28
= 2 × 2 × 5 × 3 × 7
= 420
Greatest 4 digit number = 9999.
The greatest 4 digit number is divisible by 420 = 9660.
The remainder in each case = 2.
Required number = 9660 + 2 = 9662.
Sum of digits = 9 + 6 + 6 + 2 = 23.
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