Advertisements
Advertisements
प्रश्न
Let x be the greatest number of 4 digits, which when divided by 15, 20 and 28 leaves in each case the remainder 2. The sum of digits of x is
विकल्प
19
21
23
25
Advertisements
उत्तर
23
Explanation:
L.C.M. of 15, 20 and 28
= 2 × 2 × 5 × 3 × 7
= 420
Greatest 4 digit number = 9999.
The greatest 4 digit number is divisible by 420 = 9660.
The remainder in each case = 2.
Required number = 9660 + 2 = 9662.
Sum of digits = 9 + 6 + 6 + 2 = 23.
APPEARS IN
संबंधित प्रश्न
By how much is `3/4` of 968 less than `7/8` of 1008?
There are two numbers such that the sum of twice the first number and twice the second number is 100 and the sum of thrice the first number and twice the second number is 120. Which is the larger number?
The max. value of sin x + cos x:
If an algebric expression is exactly divisible by two or more expressions, then expression is said to be
If a point (x, y) in an OXY-plane is equidistant from (-1, 1) and (4, 3), then:
The difference between the number of numbers from 2 to 100 which are not divisible by any other number except 1 and itself and the numbers which are divisible by at least one more number along with one and itself.
Three consecutive positive even numbers are such that thrice the first number exceeds double the third by 2, the third number is
A man went to the Reserve Bank of India with ₹2000. He asked the cashier to give him ₹10 and ₹20 notes only in return. The man got 150 notes in all. How many notes of ₹10 did he receive?
Three numbers which are coprimes to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is
Which of the following numbers should be added to 11158 to make it exactly divisible by 77?
