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Let X be a discrete random variable whose probability distribution is defined as follows:P(X = x) = kfor,,,kfor,,Otherwise{k(x+1) for x=1,2,3,42kx for x=5,6,70 Otherwisewhere - Mathematics

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Question

Let X be a discrete random variable whose probability distribution is defined as follows:
P(X = x) = `{{:("k"(x + 1),  "for"  x = 1"," 2"," 3"," 4),(2"k"x,  "for"  x = 5"," 6"," 7),(0,  "Otherwise"):}`
where k is a constant. Calculate Standard deviation of X.

Sum
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Solution

We know that Standard deviation (SD) = `sqrt("Variance")`

Variance= E(X2) – [E(X)]2

E(X2) = `1 xx 2/50 + 4 xx 3/50 + 9 xx 4/50 + 16 xx 5/50 + 25 xx 10/50 + 36 xx 12/50 + 49 xx 14/50`

= `2/50  + 12/50 + 36/50 + 80/50 + 250/50 + 432/50 + 686/50`

= `1498/50`

∴ Variance (X) = `1498/50 - (26/5)^2`

= `1498/50 - 676/25`

= `(1498 - 1352)/50`

= `146/50`

= 2.92

∴ S.D = `sqrt(2.92)`

= 1.7  .....(Approx)

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Chapter 13: Probability - Exercise [Page 277]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 13 Probability
Exercise | Q 49.(iii) | Page 277
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