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Question
Let the following system of equations
kx + y + z = 1
x + ky + z = k
x + y + kz = k2
has no solution. Find |k|
Options
0
1
2
3
MCQ
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Solution
2
Explanation:
`D = |(k, 1, 1),(1, k, 1),(1, 1, k)| = 0 ⇒ (k - 1)^2 (k + 2) = 0`
also `D_1 = |(1, 1, 1),(k, k, 1),(k^2, 1, k)| ≠ 0 ⇒ k ≠ 1 ⇒ k = -2`
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