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Let f: R → R be defined by f(x) = x1+x2. Then (f o f o f) (x) = ______.

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Question

Let f: R → R be defined by f(x) = `x/sqrt(1 + x^2)`. Then (f o f o f) (x) = ______.

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Solution

Let f: R → R be defined by f(x) = `x/sqrt(1 + x^2)`. Then (f o f o f) (x) = `x/sqrt(1 + 3x^2)`.

Explanation:

Given that, f(x) = `x/sqrt(1 + x^2)`

∴ (fofof)(x) = f[f(f(x))]

= `f[f(x/sqrt(1 + x^2))]`

= `f((x/sqrt(1 + x^2))/sqrt(1 + x^2/(1 + x^2)))`

= `f(x/sqrt(1 + 2x^2))`

= `(x/sqrt(1 + 2x^2))/sqrt(1 + x^2/(1 + 2x^2))`

= `x/sqrt(1 + 3x^2)`

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Inverse of a Function
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Chapter 1: Relations And Functions - Exercise [Page 17]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 1 Relations And Functions
Exercise | Q 51 | Page 17
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