English

Let a Be a Square Matrix Such that a 2 − a + I = O , Then Write a − 1 Interms of A.

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Question

Let A be a square matrix such that \[A^2 - A + I = O\], then write \[A^{- 1}\]  interms of A.

Sum
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Solution

\[\text{ Given: } A^2 - A + I = O\]
\[ A^{- 1} \left( A^2 - A + I \right) = A^{- 1} O .................(\text{Pre - multiplying both sides because }A^{- 1}\text{ exists})\]
\[\left( A^{- 1} A^2 \right) - \left( A^{- 1} A \right) + A^{- 1} I = O...................  ( A^{- 1} O = O)\]
\[ \Rightarrow A - I + A^{- 1} = O................... ( A^{- 1} I = A^{- 1} )\]
\[ \Rightarrow A^{- 1} = I - A\]

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Chapter 6: Adjoint and Inverse of a Matrix - Exercise 7.3 [Page 35]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 6 Adjoint and Inverse of a Matrix
Exercise 7.3 | Q 20 | Page 35
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