Advertisements
Advertisements
Question
Let all the students of a class is an Universal set. Let set A be the students who secure 50% or more marks in Maths. Then write the complement of set A.
Advertisements
Solution
All the students of a class is an Universal set i.e.
U = set of all the students of a class and
A = set of the students who secure 50% or more marks in Maths
Now we have to find the complement of A.
The complement of A is represented by A' and it can be calculated as
A' = U - A
A' = All the students in the class obtained less than 50 percent marks.
APPEARS IN
RELATED QUESTIONS
Which set of numbers could be the universal set for the set given below?
- P = set of integers which are multiples of 4.
- T = set of all even square numbers.
Given the universal set = {-7,-3, -1, 0, 5, 6, 8, 9}, find: A = {x : x < 2}
Given the universal set = {-7,-3, -1, 0, 5, 6, 8, 9}, find: B = {x : -4 < x < 6}
Given the universal set = {x : x ∈ N and x < 20}, find:
C = {x : x is divisible by 4}
Given, universal set = {x : x ∈ N, 10 ≤ x ≤ 35}.
A = {x ∈ N : x ≤ 16} Find: A'
Given, universal set = {x : ∈ N, 10 ≤ x ≤ 35}.
B = {x : x > 29} Find: B'.
Given universal set = {x ∈ Z : -6 < x ≤6}.
N = {n : n is non-negative number}
Find: N'
For the universal set {4, 5, 6, 7, 8, 9, 10, 11,12,13} ; find the subset of B = {odd numbers greater than 8}.
Also, find a complement of B.
For the universal set {4, 5, 6, 7, 8, 9, 10, 11,12,13} ; find the subset of C = {prime numbers}.
Also, find a complement of C.
For the universal set {4, 5, 6, 7, 8, 9, 10, 11,12,13} ; find the subset of D = {even numbers less than 10}.
Also, find a complement of D.
If A = {4, 5, 6, 7, 8} and B = {6, 8, 10, 12}, find: A - B
If A = {3, 5, 7, 9, 11} and B = {4, 7, 10}, find: n(B)
If A = {2, 4, 6, 8} and B = {3, 6, 9, 12}, find: (A ∩ B) and n(A ∩ B)
If A = {3, 5, 7, 9, 11} and B = {4, 7, 10}, find: n (B)
If P = {x : x is a factor of 12} and Q = {x: x is a factor of 16}, find : n(P)
If P = {x : x is a factor of 12} and Q = {x: x is a factor of 16}, find : Q – P and n(Q – P).
