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Let a pair of dice be thrown and the random variable X be the sum of the numbers that appear on the two dice. Find the mean or expectation of X and variance of X.

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Question

Let a pair of dice be thrown and the random variable X be the sum of the numbers that appear on the two dice. Find the mean or expectation of X and variance of X

Sum
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Solution

The sample space of the experiment consists of 36 elementary events in the form of ordered pairs (xi, yi), where xi = 1, 2, 3, 4, 5, 6 and yi = 1, 2, 3, 4, 5, 6.

The random variable X, i.e., the sum of the numbers on the two dice takes the values 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 or 12.

X = xi P(xi) xiP(xi) xi2P(xi)
2 `1/36` `2/36`

`4/36`

3 `2/36` `6/36` `18/36`
4 `3/36` `12/36` `48/36`
5 `4/36` `20/36` `100/36`
6 `5/36` `30/36` `180/36`
7 `6/36` `42/36` `294/36`
8 `5/36` `40/36` `320/36`
9 `4/36` `36/36` `324/36`
10 `3/36` `30/36` `300/36`
11 `2/36` `22/36` `242/36`
12 `1/36` `12/36` `144/36`
    `sum_("i" = 1)^"n"x"P"(x_"i") = 252/36` = 7 `sum_("i" = 1)^"n"x_"i"^2"P"(x_"i") = 1974/36`

∴ E(X) = `sum_("i" = 1)^11x_"i""P"(x_"i")` = 7

E(x2) = `sum_("i" = 1)^"n"x_"i"^2"P"(x_"i") = 1974/36`

Var(X) = E(X2) – [E(X)]2 = `1974/36 - (7)^2`

= `1974/36 - 49`

= `35/6`

= 5.83

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Chapter 2.7: Probability Distributions - Long Answers III

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