English

Find the probability distribution of the number of successes in two tosses of a die, where a success is defined as six appears on at least one die

Advertisements
Advertisements

Question

Find the probability distribution of the number of successes in two tosses of a die, where a success is defined as six appears on at least one die

Sum
Advertisements

Solution

Success is defined as a number six appears on at least one die.

Let X denotes the number of successes.

∴ The possible values of X are 0, 1, 2.

Let P(getting six) = p

= `1/6`

∴ q = 1 – p

= `1 - 1/6`

= `5/6`

∴ P(X = 0) = P(no success)

= qq

= q2

= `25/36`

P(X =1) = P(one success)

= pq + qp

= 2pq

= `2 xx 1/6 xx 5/6`

= `10/36`

P(X = 2) = P(two successes)

= pp

= p2

= `1/36`

∴ Probability distribution of X is as follows:

X 0 1 2
P(X = x) `25/36` `10/36` `1/36`
shaalaa.com
  Is there an error in this question or solution?
Chapter 2.7: Probability Distributions - Short Answers II
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×