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Let A(i^+2j^+3k^),B(j^+k^) and C(3i^+2j^+2k^) are position vectors of vertices of ΔABC and the circumradius of ΔABC is R then 4R211 is ______.

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Question

Let `A(hati + 2hatj + 3hatk), B(hatj + hatk)` and `C(3hati + 2hatj + 2hatk)` are position vectors of vertices of ΔABC and the circumradius of ΔABC is R then `(4R^2)/11` is ______.

Options

  • 0.00

  • 1.00

  • 2.00

  • 3.00

MCQ
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Solution

Let `A(hati + 2hatj + 3hatk), B(hatj + hatk)` and `C(3hati + 2hatj + 2hatk)` are position vectors of vertices of ΔABC and the circumradius of ΔABC is R then `(4R^2)/11` is 1.00.

Explanation:


Given ΔABC is right angled triangle

2R = `sqrt(9 + 1 + 1)`

2R = `sqrt(11)`

⇒ 4R2 = 11

⇒ `(4R^2)/11` = 1

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Vector and Cartesian Equations of a Line - Position Vector of a Point in a Space
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