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प्रश्न
Let `A(hati + 2hatj + 3hatk), B(hatj + hatk)` and `C(3hati + 2hatj + 2hatk)` are position vectors of vertices of ΔABC and the circumradius of ΔABC is R then `(4R^2)/11` is ______.
पर्याय
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MCQ
रिकाम्या जागा भरा
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उत्तर
Let `A(hati + 2hatj + 3hatk), B(hatj + hatk)` and `C(3hati + 2hatj + 2hatk)` are position vectors of vertices of ΔABC and the circumradius of ΔABC is R then `(4R^2)/11` is 1.00.
Explanation:
Given ΔABC is right angled triangle
2R = `sqrt(9 + 1 + 1)`
2R = `sqrt(11)`
⇒ 4R2 = 11
⇒ `(4R^2)/11` = 1
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