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It is given that ΔАBC ~ ΔDFE, ∠A = 30°, ∠C = 50°, AB = 5cm, AC = 8 cm and DF = 7.5 cm. Then DE = ______ and F = ______.

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Question

It is given that ΔАBC ~ ΔDFE, ∠A = 30°, ∠C = 50°, AB = 5cm, AC = 8 cm and DF = 7.5 cm. Then DE = ______ and F = ______.

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Solution

It is given that ΔАBC ~ ΔDFE, ∠A = 30°, ∠C = 50°, AB = 5cm, AC = 8 cm and DF = 7.5 cm. Then DE = 12 cm and F = 100°.

Explanation:

From ΔABC ~ ΔDFE the correspondence is A↔D, B↔F, C↔E, so AB ↔ DF and AC ↔ DE. By similarity corresponding sides are proportional.

Scale factor `k = (DF)/(AB)`

= `7.5/5`

= 1.5 

So DE = k × AC

= 1.5 × 8

= 12 cm

Angles correspond likewise, so ∠F = ∠B.

Since ∠A = 30° and ∠C = 50°

∠B = 180° – 30° – 50° = 100°

Hence ∠F = 100°.

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Chapter 7: Triangles - FILL IN THE BLANK TYPE QUESTIONS (FBQs) [Page 7.103]

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R.D. Sharma Mathematics [English] Class 10
Chapter 7 Triangles
FILL IN THE BLANK TYPE QUESTIONS (FBQs) | Q 10. | Page 7.103
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