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Integrate the functions: 11+cotx

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Question

Integrate the functions:

`1/(1 + cot x)`

Sum
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Solution

Let `I = int 1/ (1 + cot x) dx = int 1/ (1 + cos x/sinx) dx`

`= int sin/(sin x + cos x) dx`

`= 1/2 int (2 sin x)/ (sinx + cos x) dx`

`= 1/2 int ((sin x +  cos x) - (cos x - sin x))/ ((sin x + cos x)) dx`

`= 1/2 int 1 dx - 1/2 int (cos x - sin x)/ (sin x + cos x) dx`

`= 1/2 x - 1/2 int (cos x - sin x)/ (sin x +  cos x) dx + C_1`

`I = x/2 - 1/2 I_1 + C_1`                  ........(i)

Where, `I_1 = int (cos x - sin x)/ (sin x +  cos x) dx`

Put sin x +  cos x = t 

⇒ (cos x - sin x) dx = dt

⇒ `I_1 = int dt/t = log |t| + C_2`

`= log |cos x + sin x| + C_2`              ......(ii)

From (i) and (ii), we get

⇒ `I = 1/2 x - 1/2 log |cos x + sin x| + C` 

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Chapter 7: Integrals - Exercise 7.2 [Page 305]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.2 | Q 32 | Page 305

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