Question

In what ratio is the line joining (2, -1) and (-5, 6) divided by the y axis ?

Answer 1

Let the point P (0, y) lies on y-axis which divides the line segment AB in the ratio k : 1. 

Coordinates of P are ,

0 = `(-5 "k" + 2)/("k" + 1) ,  "y" = (6"k" - 1)/("k" + 1)`

⇒ 5 k = 2

⇒ k = `2/5`

Hence, the required ratio is 2 : 5.