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Question
In the quadrilateral ABCD, AD = CD and ∠A = 90° = ∠C.
Prove that AB = BC.

Theorem
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Solution
Given: In quadrilateral ABCD, AD = CD and ∠A = 90°, ∠C = 90°
To Prove: AB = BC
Proof:
1. Since AD = CD and ∠A = ∠C = 90°, triangles ABD and CBD share the side BD.
2. Consider triangles ABD and CBD:
AD = CD ...(Given)
∠A = ∠C = 90° ...(Given)
BD = BD ...(Common side)
3. By RHS (Right angle-Hypotenuse-Side) congruence criterion, △ABD ≅ △CBD.
4. Therefore, corresponding parts of congruent triangles are equal, so AB = BC.
Hence, in quadrilateral ABCD, AB = BC is proved.
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