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In the quadrilateral ABCD, AD = CD and ∠A = 90° = ∠C. Prove that AB = BC. - Mathematics

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Question

In the quadrilateral ABCD, AD = CD and ∠A = 90° = ∠C.

Prove that AB = BC.

Theorem
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Solution

Given: In quadrilateral ABCD, AD = CD and ∠A = 90°, ∠C = 90°

To Prove: AB = BC

Proof:

1. Since AD = CD and ∠A = ∠C = 90°, triangles ABD and CBD share the side BD.

2. Consider triangles ABD and CBD:

AD = CD   ...(Given)

∠A = ∠C = 90°   ...(Given)

BD = BD   ...(Common side)

3. By RHS (Right angle-Hypotenuse-Side) congruence criterion, △ABD ≅ △CBD.

4. Therefore, corresponding parts of congruent triangles are equal, so AB = BC.

Hence, in quadrilateral ABCD, AB = BC is proved.

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Chapter 8: Triangles - EXERCISE 8A [Page 83]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 8 Triangles
EXERCISE 8A | Q 4. | Page 83
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