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Question
In the given figure, quad. ABCD is circumscribed, touching the circle at P, Q, R and S. If AP = 5 cm, BC = 7 cm and CS = 3 cm. Then, the length AB = ?
Options
9 cm
10 cm
12 cm
8 cm
MCQ
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Solution
9 cm
Explanation:
Since the lengths of tangents drawn from an external point to a circle are equal, we have AQ = AP = 5 cm.
CR = CS = 3 cm and BR = (BC – CR) = (7 – 3) cm = 4 cm.
BQ = BR = 4 cm.
∴ AB = (BR + BQ)
= (5 + 4) cm
= 9 cm
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