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Question
In the given figure, PT and QT are tangents to a circle such that ∠TPS = 45° and ∠TQS = 30°. Then, the value of x is:

Options
30°
45°
75°
105°
MCQ
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Solution
105°
Explanation:
By the alternate-segment theorem, the angle between a tangent and a chord equals the angle in the opposite arc.
So, ∠TPS = ∠PQS = 45° and ∠TQS = ∠QPS = 30°.
In triangle PQS the angles sum to 180°.
So, x = 180° – 45° – 30° = 105°.
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