Question

In the given figure, ∠PQR = 90°, seg QN ⊥ seg PR, PN = 9, NR = 16, find QN.

Answer 1

In △ PQR, ∠ PQR = 90°.

seg QN ⊥ hypotenuse PR.

∴ by the theorem of geometric mean, 

QN² = PN × NR

= 9 × 16

∴ QN = 3 × 4      ...(Taking square roots of both the sides)

∴ QN = 12