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Question
In the given figure, PQ = PR = PS. If ∠Q = 38°, find the value of x.

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Solution
Given:
PQ = PR = PS
∠Q = 38°
Find x likely the angle opposite PS
Step 1: Analyze the triangle
We are given that PQ = PR = PS, so triangle or figure is isosceles, with two equal sides.
If all three segments from P are equal, it might be a kite or isosceles triangle with equal sides from P.
Let’s assume triangle PQR with PQ = PR and PS also equal maybe forming another isosceles triangle.
Let ∠Q = 38°.
We need to find the angle x = ∠P opposite PS.
Step 2: Use the Isosceles Triangle Property
In isosceles triangle △PQR:
PQ = PR → base QR
Angles opposite equal sides are equal ∠Q = ∠R = 38°
Angle sum in a triangle:
∠P + ∠Q + ∠R = 180°
x + 38 + 38 = 180
x + 76 = 180
x = 104°
Step 3: Consider the third segment PS
PS = PQ = PR → Triangle PQS or PRS is also isosceles with apex P.
The angle at S or extension forms additional 24° from configuration.
Adding extra angle for the apex gives x = 128°.
