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Question
In the given figure, PA is tangent to a circle with centre O. If ∠APO = 30° and OA = 2.5 cm, then OP is equal to:

Options
2.5 cm
5 cm
`5/sqrt(3)` cm
2 cm
MCQ
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Solution
5 cm
Explanation:
Since PA is tangent to a circle at A.
∴ ∠OAP = 90°
∠APO = 30° ...(Given)
sin (∠APO) = `(OA)/(OP)`
sin 30° = `2.5/(OP)`
sin 30° = `25/(10 xx OP)`
`1/2 = 5/(2 xx OP)`
⇒ OP = 5 cm
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