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Question
In the given figure, O is the centre of the circle, AB is side of a regular pentagon, then angle ACB is equal to:
Options
36°
72°
50°
40°
MCQ
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Solution
36°
Explanation:
Join OA and OB.
Given,
AB is side of a regular pentagon.
∴ ∠AOB = `(360°)/5` = 72°
We know that,
The angle which an arc of a circle subtends at the center is double that which it subtends at any point on the remaining part of the circumference.
∴ ∠AOB = 2∠ACB
∠ACB = `(∠AOB)/2 = (72°)/2` = 36°
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