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In the given figure, O is the centre of a circle, PQ is a chord and the tangent PT at P makes an angle of 50° with PQ. Then, ∠POQ = ?

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Question

In the given figure, O is the centre of a circle, PQ is a chord and the tangent PT at P makes an angle of 50° with PQ. Then, ∠POQ = ?

Options

  • 130°

  • 100°

  • 90°

  • 75°

MCQ
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Solution

100°

Explanation:

By the tangent–chord (alternate-segment) theorem, the angle between the tangent PT and chord PQ equals the angle subtended by chord PQ at the circumference so that inscribed angle = 50°. The central angle subtending the same chord is twice the inscribed angle, so ∠POQ = 2 × 50° = 100°.

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Chapter 8: Circles - TEST YOURSELF [Page 513]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 8 Circles
TEST YOURSELF | Q 1. | Page 513
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