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Question
In the given figure, O is the centre of a circle and PT is the tangent to the circle. If PQ is a chord such that ∠QPT = 50° then ∠POQ = ?

Options
100°
90°
80°
75°
MCQ
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Solution
100°
Explanation:

Mark a point R in the alternate segment.
Join PR and QR.
Then, ∠PRQ = ∠QPT = 50° ...[Angles in alternate segments]
Now, ∠POQ = 2∠PRQ = 100° ...[∵ Angle at the centre is double the angle on the circle]
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