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Question
In the given figure, if ΔACP ~ ΔDCP, then:
Options
∠DCP = 60°
∠DCP = 30°
∠DCP = 90°
∠DCP = 30°
MCQ
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Solution
∠DCP = 30°
Explanation:
Given: ΔACP ~ ΔDCP
In ΔACP:
∠CAP = 90°
∠APC = 60°
Using angle sum property in ΔACP:
∠ACP + ∠CAP + ∠APC = 180°
∠ACP + 90° + 60° = 180°
∠ACP = 180° – 150°
∠ACP = 30°
Since △ACP ∼ △DCP, the corresponding angles are equal:
∠DCP = ∠ACP
∠DCP = 30°
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