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In the given figure, EF is parallel to BC. If area of triangle ABC is 576 cm2, the area of triangle AEF is ______.

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Question

In the given figure, EF is parallel to BC. If area of triangle ABC is 576 cm2, the area of triangle AEF is ______.

The image displays a triangle ABC with a horizontal base AB, featuring an internal vertical segment EF of length $8\text{ cm}$ parallel to the vertical side BC of length $12\text{ cm}$, as indicated by matching directional arrows. It illustrates proportional segment ratios and triangle similarity principles for solving numerical geometry problems.

Options

  • 128 cm2

  • 288cm2

  • 256 cm2

  • 768 cm2

MCQ
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Solution

In the given figure, EF is parallel to BC. If area of triangle ABC is 576 cm2, the area of triangle AEF is 256 cm2.

Explanation:

From figure,

In △ AEF and △ ABC,

⇒ ∠EAF = ∠BAC (Common angle)

⇒ ∠AEF = ∠ABC (Corresponding angle)

∴ △ AEF ~ △ ABC (By A.A. axiom)

We know that,

The areas of two similar triangles are proportional to the squares of their corresponding sides.

∴ `("Area of" △ AEF​)/("Area of" △ ABC) = (EF^2)/(BC^2)​`

⇒ `("Area of" △ AEF​)/576 ​= 8^2/12^2` 

⇒ `("Area of" △ AEF​)/576 ​= 64/144` 

⇒ Area of △ AEF = `64/144 ​× 576`

⇒ Area of △ AEF = 64 × 4

= 256 cm2

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Chapter 15: Similarity (With Applications to Maps and Models) - TEST YOURSELF [Page 232]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 15 Similarity (With Applications to Maps and Models)
TEST YOURSELF | Q 1. (e) | Page 232
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