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In the given figure, AP is bisector of angle A of △ ABC and DP is perpendicular bisector of side AB, then:

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Question

In the given figure, AP is bisector of angle A of △ABC and DP is perpendicular bisector of side AB, then:

The image displays a triangle $ABC$, an angle bisector construction at vertex $A$ featuring construction arcs and a dotted line passing through point $P$ with hash marks, and a dotted perpendicular line segment dropping from point $P$ to side $AB$ and extending down to point $D$ with a construction hash mark.

Options

  • P is incentre of △ABC.

  • P is circumcentre of △ABC.

  • PB bisects angle B.

  • none of these

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Solution

none of these

Explanation:

The incenter of a triangle is the intersection point of all the three interior angle bisectors of the triangle.

The circumcenter of a triangle is defined as the point where the perpendicular bisectors of the sides of triangle intersect.

Since,

In the given figure, P is intersection of an angle bisector and perpendicular bisector of a side.

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Chapter 19: Constructions (Circles) - EXERCISE 19 [Page 298]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 19 Constructions (Circles)
EXERCISE 19 | Q 1. (a) | Page 298
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