Question

In the given figure, ABCD is a cyclic quadrilateral where diagonals intersect at P such that ∠DBC = 40° and ∠BAC = 60° find ∠BCD

Answer 1

∠BAC – ∠BDC = 60°  ...[Angles at the circumference to the same segment]

∠BCD + ∠BDC + ∠CBD = 180° ...(Sum of the three angles of A is 180°)

∠BCD + 60° + 40° = 180°

∠BCD = 180° – 100°

= 80°