Question

In the given figure, AB || CD || EF. If AC = 12, CE = 9, BD = 8, then complete the following activity to find DF. 

Activity:

AB || CD || EF

∴ `(AC)/square = square/(DF)`    ...(Property of three parallel lines and their transversals)

∴ `12/square = square/(DF)`

∴ DF = `(8 xx 9)/square`

∴ DF = `square`.

Answer 1

AB || CD || EF

∴ \[\frac{AC}{\boxed{CE}}\] = \[\frac{\boxed{BD}}{DF}\]    ...(Property of three parallel lines and their transversals)

∴ \[\frac{12}{\boxed{9}}\] = \[\frac{\boxed{8}}{DF}\]

∴ DF = \[\frac{8 × 9}{\boxed{12}}\]

∴ DF = \[\boxed{6}\].