Advertisements
Advertisements
Question
In the given figure, a tower AB is 20 m high and BC, its shadow on the ground is `20sqrt(3)` m long. The sun's altitude is ______.

Options
30°
45°
60°
none of these
MCQ
Fill in the Blanks
Advertisements
Solution
In the given figure, a tower AB is 20 m high and BC, its shadow on the ground is `20sqrt(3)` m long. The sun's altitude is 30°.
Explanation:

Let AB = m be the tower and `BC = 20sqrt(3)` be the length of its shadow.
Let ∠ACB = θ.
Then, `tan θ = (AB)/(AC)`
= `20/(20sqrt(3))`
= `1/sqrt(3)`
= tan 30°
∴ θ = 30°
shaalaa.com
Is there an error in this question or solution?
