English

In the given figure, a square OABC is inscribed in a quadrant OPBQ of a circle. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14.]

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Question

In the given figure, a square OABC is inscribed in a quadrant OPBQ of a circle. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14.]

Sum
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Solution

Construction: Join OB

In right triangle AOB

OB= OA+ AB

= 202 + 202

= 400 + 400

= 800

∴ OB= 800

Area of the shaded region = Area of quadarant OPBQ – Area of square OABC

`=1/4pi("OB")^2 - ("OA")^2`

`=1/4xx3.14xx800-400`

= 2(314) – 400

= 628 – 400

= 228 cm2

Hence, the area of the shaded region is 228 cm2.

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Chapter 16: Area of Circle, Sector and Segment - EXERCISE 16B [Page 750]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 16 Area of Circle, Sector and Segment
EXERCISE 16B | Q 39. | Page 750
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