Question

In the formula `barx = a + h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution, u_i = ______.

Options

• `(x_i + a)/h`

• `h(x_i - a)`

• `(x_i - a)/h`

• `(a - x_i)/h`

Answer 1

In the formula `barx = a + h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution, u_i = `underlinebb((x_i - a)/h)`.

Explanation:

According to the question,

`barx = a + h((sumf_iu_i)/(sumf_i))`

Above formula is a step deviation formula.

In the above formula,

x_i is data values,

a is assumed mean,

h is class size,

When class size is same we simplify the calculations of the mean by computing the coded mean of u₁, u₂, u₃ …..,

Where u_i = `(x_i - a)/h`