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Question
In the formula \( t_{10} = a + 9d = 25 \), which value is used in place of \( (n - 1) \)?
Options
\( 8 \)
\( 10 \)
\( 25 \)
\( 9 \)
MCQ
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Solution
Using \( t_{n} = a + (n - 1)d \) with \( n = 10 \) gives \( t_{10} = a + (10 - 1)d = a + 9d \). Hence \( (n - 1) = 9 \) common differences are added to the first term.
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