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In the following situation, involved make an arithmetic progression? and why? The cost of digging a well after every metre of digging, - Mathematics

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Question

In the following situation, involved make an arithmetic progression? and why?

The cost of digging a well after every metre of digging, when it costs Rs 150 for the first metre and rises by Rs 50 for each subsequent metre.

Sum
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Solution

Cost of digging for first metre = 150

Cost of digging for first 2 metres = 150 + 50 = 200

Cost of digging for first 3 metres = 200 + 50 = 250

Cost of digging for first 4 metres = 250 + 50 = 300

Clearly, 150, 200, 250, 300 … 

Check:

a = 150

d1 - a2 - a1

= 200 - 150

= 50

d2 = a3 - a2

= 250 - 200

= 50

d3 = a4 - a3

= 300 - 250

= 50

Common difference = 50

Here the common difference is the same hence this series is A.P.

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Chapter 5: Arithmetic Progressions - Exercise 5.1 [Page 99]

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NCERT Mathematics [English] Class 10
Chapter 5 Arithmetic Progressions
Exercise 5.1 | Q 1.3 | Page 99
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