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Question
In the following, show that the given numbers are the solution of the given equation:
`x^2 + 3sqrt2x - 8=0; x = sqrt2`
Sum
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Solution
Given:
`x^2 + 3sqrt2x - 8=0`
Verification
Substitute `x = sqrt2` in the left-hand side (LHS):
`x^2 + 3sqrt2x - 8`
`= (sqrt2)^2 + 3sqrt2 (sqrt2) - 8`
= 2 + 3(2) − 8
= 2 + 6 − 8
= 0
Since LHS = 0, which equals the RHS,
`x = sqrt2`is a solution of `x^2 + 3sqrt2x - 8=0`
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Chapter 5: Quadratic equations - Exercise 5A [Page 57]
