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Question
In the following, show that the given numbers are the solution of the given equation:
`6x^2 + x − 7 = 0; x = 7/6`
Sum
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Solution
Given:
6x2 + x − 7 = 0
Verification
Substitute x = `7/6` in the left-hand side (LHS):
`6 (7/6)^2 + 7/6 - 7`
`= 6xx49/36 + 7/6 - 7`
`= 49/6 + 7/6 - 7`
`= 56/6 - 7`
`= 28/3 -7`
`= 28/3 - 21/3`
`= 7/3`
Since the LHS ≠ 0,
`x = 7/6` is not a solution of 6x2 + x − 7 = 0
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Chapter 5: Quadratic equations - Exercise 5A [Page 57]
