Question

In the following reaction

\[\begin{array}{cc}
\phantom{}\ce{\underset{}{C6H5CH2Br} ->[1. Mg, Ether][2. H3O+] \underset{}{X}}\\
\end{array}\],

the product 'X' is

Options

• C₆H₅CH₂OCH₂C₂C₆H₅

• C₆H₅CH₂OH

• C₆H₅CH₃

• C₆H₅CH₂CH₂C₆H₅

Answer 1

C₆H₅CH₃

Explanation: