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Question
In the following reaction between lead sulphide and hydrogen peroxide:
\[\ce{PbS_{(s)} + 4H2O2_{(aq)} -> PbSO4_{(s)} + 4H2O_{(l)}}\]
- Which substance is reduced?
- Which substance is oxidised?
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Solution
- Reduction is the loss of oxygen. Hydrogen peroxide (H2O2) loses oxygen atoms as it converts into water (H2O). Therefore, Hydrogen peroxide (H2O2) is reduced.
- Oxidation is the gain of oxygen. Lead sulphide (PbS) gains four oxygen atoms to form lead sulphate (PbSO4). Therefore, Lead sulphide (PbS) is oxidised.
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