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Question
In the following figure the diameter of the inner circle is 3 m and that of outer circle is 11 m. Taking π to be `22/7`, find the area of the shaded region.

Sum
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Solution
Given: Inner circle diameter = 3 m, outer circle diameter = 11 m; take π = `22/7`.
Step-wise calculation:
1. Radius of inner circle r = `3/2` = 1.5 m.
2. Radius of outer circle R = `11/2` = 5.5 m.
3. Area of shaded region (annulus) = π(R2 – r2).
4. R2 = 5.52
= 30.25
r2 = 1.52
= 2.25
5. R2 – r2 = 28.0
6. Area = `22/7 xx 28`
= 22 × 4
= 88 m2
Area of the shaded region = 88 m2.
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