Advertisements
Advertisements
Question
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then
Mid point of AE is ______
Advertisements
Solution
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then
Mid point of AE is C
Explanation:
∵ AB + BC = CD + DE
⇒ AC = CE
∴ Mid point of AE is C.
APPEARS IN
RELATED QUESTIONS
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then
AD = AB + ______
Two angles can have exactly five points in common.
In the following figure, is AB + BC = CA?
Use the figure to name Five points.
Consider the following figure of line \[\overleftrightarrow{MN}\]. Say whether the following statement is true or false in the context of the given figure.
O is not an initial point of `vec("OP")`.
Consider the following figure of line \[\overleftrightarrow{MN}\]. Say whether the following statement is true or false in the context of the given figure.
N is the initial point of `vec("NP")` and `vec("NM")`.
A point has:
A point is usually denoted by:
Three or more points lying on the same straight line are called:
Non-collinear points are:
