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Question
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then
Mid point of AE is ______
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Solution
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then
Mid point of AE is C
Explanation:
∵ AB + BC = CD + DE
⇒ AC = CE
∴ Mid point of AE is C.
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