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Question
In the following figure, A is the centre of the arc of the circle. Find the perimeter and the area of the shaded region, where length and breadth are 12 cm and 7 cm respectively.

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Solution
1. Perimeter of the shaded region
The perimeter of the shaded region consists of:
1. The bottom side of the rectangle: 12 cm.
2. The two vertical sides of the rectangle: 7 cm + 7 cm = 14 cm.
3. The two parts of the top side of the rectangle: Since the semicircle's diameter is 7 cm and it is centered on the 12 cm side, the remaining straight top sections are 12 – 7 = 5 cm.
4. The length of the semicircular arc: Arc length = π × r.
Using `π = 22/7`:
Arc length = `22/7 xx 3.5`
= `22/7 xx 7/2`
= 11 cm
Step 3: Sum all components
Total perimeter = 12 + 7 + 7 + 5 + 11
Total perimeter = 42 cm
The perimeter of the shaded region is 42 cm.
2. Area of the shaded region
Area of rectangle = Length × Breadth
Area of rectangle = 12 × 7 = 84 cm2
Area of semicircle = `1/2 xx π xx r^2`
Area of semicircle = `1/2 xx 22/7 xx (3.5)^2`
Area of semicircle = `1/2 xx 22/7 xx 49/4`
= `(11 xx 7)/4`
= 19.25 cm2
Step 3: Subtract the semicircle area from the rectangle area
Area of shaded region = Area of rectangle – Area of semicircle
Area of shaded region = 84 – 19.25 = 64.75 cm2
The area of the shaded region is 64.75 cm2.
