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In the following, DE || BC. If DE = 6 cm, BC = 12 cm, find the ratio of Area (ΔADE) and Area (quad. DECB).

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Question

In the following, DE || BC. If DE = 6 cm, BC = 12 cm, find the ratio of Area (ΔADE) and Area (quad. DECB).

Sum
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Solution

Given: DE || BC, DE = 6 cm, BC = 12 cm.

Step-wise calculation:

1. Because DE || BC, ΔADE ~ ΔABC (corresponding sides proportional).

The ratio of corresponding linear sides = `(DE)/(BC)`

= `6/12`

= `1/2`

2. Ratio of areas of similar triangles = (Ratio of sides)2.

⇒ `(Area(ΔADE))/(Area(ΔABC)) = (1/2)^2`

= `1/4`

3. Quadrilateral DECB is the part of ΔABC outside ΔADE, so

Area (DECB) = Area (ΔABC) – Area (ΔADE) = `(1 - 1/4)`

Area (ΔABC) = `3/4` Area (ΔABC)

4. Therefore `(Area (ΔADE))/(Area(DECB)) = (1/4)/(3/4) = 1/3`.

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Chapter 7: Triangles - EXERCISE 7.5 [Page 7.77]

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R.D. Sharma Mathematics [English] Class 10
Chapter 7 Triangles
EXERCISE 7.5 | Q 3. (iv) | Page 7.77
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