Question

In the figure AB in parallel to CD. Find x°, y° and z°

Answer 1

Given AB || CD

Then AD and BC are transversals.

x = 48°, alternate interior angles; AD is transversal y = 60°, alternate interior angles, BC is transversal

∠AEB + 48° + y° = 180°, ...(sum of angles of a triangle is 180°)

∠AEB + 48° + 60° = 180°

∠AEB + 108° = 180°

∠AEB + 108° − 108° = 180° − 108°

∠AEB = 72°

∠AEB + z° = 180° ...[Linear pair]

72° + z° = 180°

72° + z° − 72° = 180° − 72°

z° = 108°

x = 48°, y = 60°, z = 108°