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In the adjoining figure, SR || PQ and ∠PQR = 90°. If PQ = 7 cm, PR = 25 cm and SR = 17 cm, find the length of PS. - Mathematics

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Question

In the adjoining figure, SR || PQ and ∠PQR = 90°. If PQ = 7 cm, PR = 25 cm and SR = 17 cm, find the length of PS.

Sum
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Solution

Given: PQ || SR

∠PQR = 90°

PQ = 7 cm

PR = 25 cm

SR = 17 cm

Find PS.

Step-wise calculation:

1. Place P at (0, 0) and Q at (7, 0).

So, PQ = 7 along the x-axis and ∠PQR = 90° makes QR vertical.

2. Let R = (7, y).

Use PR = 25:

PR2 = (7 – 0)2 + (y – 0)2 

⇒ 252 = 72 + y2

y2 = 625 – 49

= 576 

⇒ y = 24

So, R = (7, 24).

3. SR || PQ is horizontal and SR = 17.

So, S is 17 units left of R:

S = (7 – 17, 24)

= (–10, 24)

4. Compute PS:

PS2 = (–10 – 0)2 + (24 – 0)2 

= 100 + 576

= 676

⇒ `PS = sqrt(676)`

⇒ PS = 26 cm

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Chapter 10: Pythagoras Theorem - Exercise 10A [Page 211]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 10 Pythagoras Theorem
Exercise 10A | Q 15. | Page 211
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