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Question
In the adjoining figure, seg DE is the chord of the circle with center C, seg CF ⊥ seg DE and DE = 16 cm, then find the length of DF?
Sum
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Solution
In the given figure, seg CF ⊥ Chord DE
∴ DF ≅ DE ...[A perpendicular drawn from the centre of a circle on its chord bisects the chord.]
∴ `DF = 1/2 DE`
= `1/2 xx 16` ...[Given]
∴ DF = 8 cm
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