Question

In the adjoining figure, ΔACB ∼ ∆APQ. If BC = 10 cm, PQ = 5 cm, BA = 6.5 cm and AP = 2.8 cm find the area (∆ACB) : area (∆APQ).

Answer 1

∆ACB ∼ ∆APQ.
Then, `"area (∆ACB)"/"area (∆APQ)" = "BC"^2/"PQ"^2`
= `(10)^2/(5)^2`
= `(100)/(25)`
= `(4)/(1)`
Required ratio is 4 : 1.