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Question
In the adjoining diagram, ST is not parallel to PQ. The necessary and sufficient conditions for ΔPQR ~ ΔTSR is:

Options
∠PQR = ∠STR
∠QPR = ∠TSR
∠PQR = ∠TSR
∠PRQ = ∠RST
MCQ
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Solution
∠PQR = ∠TSR
Explanation:
Two triangles are similar iff two pairs of corresponding angles are equal (AA criterion).
For ΔPQR ~ ΔTSR the correspondence is P↔T, Q↔S, R↔R, so the angle at P must equal the angle at T(∠QPR = ∠STR) and the angle at Q must equal the angle at S(∠PQR = ∠TSR).
This gives the required similarity.
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