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In the adjoining diagram, ST is not parallel to PQ. The necessary and sufficient conditions for ΔPQR ~ ΔTSR is: - Mathematics

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Question

In the adjoining diagram, ST is not parallel to PQ. The necessary and sufficient conditions for ΔPQR ~ ΔTSR is:

Options

  • ∠PQR = ∠STR

  • ∠QPR = ∠TSR

  • ∠PQR = ∠TSR

  • ∠PRQ = ∠RST

MCQ
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Solution

∠PQR = ∠TSR

Explanation:

Two triangles are similar iff two pairs of corresponding angles are equal (AA criterion).

For ΔPQR ~ ΔTSR the correspondence is P↔T, Q↔S, R↔R, so the angle at P must equal the angle at T(∠QPR = ∠STR) and the angle at Q must equal the angle at S(∠PQR = ∠TSR).

This gives the required similarity.

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Chapter 23: Competency focused practice questions - COMPETENCY FOCUSED PRACTICE QUESTIONS [Page 523]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 23 Competency focused practice questions
COMPETENCY FOCUSED PRACTICE QUESTIONS | Q 27. | Page 523
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