Advertisements
Advertisements
Question
In Q. No. 14, write the sign of c.
Short/Brief Note
Advertisements
Solution
The parabola `y = ax^2 + bx + c` cuts y-axis at point P which lies on y-axis. Putting x=0 in `y= ax^2 + bx + c`, we get y = c. So the coordinates of P are `(0,c)`. Clearly, P lies on OY. Therefore `c > 0`

Hence, the sign of c is c > 0
shaalaa.com
Is there an error in this question or solution?
