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Question
In ΔPQR, ∠R = 90°, P = (8, −7), Q = (2, 1) and QR = 8 units. Find the length of the PQ and PR.

Sum
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Solution
∠R = 90°
P(8, −7)
Q(2, 1)
QR = 8 units
We need PQ and PR.
Step 1: Find PQ using distance formula
PQ = `sqrt((x_2 − x_1)^2 + (y_2 − y_1))`
PQ = `sqrt((2 − 8)^2 + (1 − (−7))^2)`
PQ = `sqrt((−6)^2 + (8)^2)`
PQ = `sqrt(36 + 64)`
PQ = `sqrt100`
PQ = 10 units
Step 2: Use Pythagoras Theorem
Since △PQR is right-angled at R:
PQ2 = PR2 + QR2
102 = PR2 + 64
PR2 = 36
PR = 6
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