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Question
In ΔPQR, ∠P = 80° and ∠Q = 43°. Arrange the sides in descending order of length.
Sum
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Solution
Given:
Triangle ΔPQR with ∠P = 80°, ∠Q = 43°
Step 1: Find the third angle
∠R = 180° – (80° + 43°) = 180° – 123° = 57°
So, the angles are ∠P = 80°, ∠Q = 43°, ∠R = 57°
Step 2: Relating sides to angles
In any triangle, the largest angle is opposite the longest side and the smallest angle is opposite the shortest side.
Largest angle = ∠P = 80° → Opposite side = QR ...(Longest side)
Next = ∠R = 57° → Opposite side = PQ ...(Middle side)
Smallest angle = ∠Q = 43° → Opposite side = PR ...(Shortest side)
The sides in descending order of length are QR > PQ > PR.
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