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Question
In ΔPQR, NM || RQ. If PM = 15, MQ = 10, NR = 8, then find PN.
Sum
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Solution
In ΔPQR, NM || RQ ......[Given]
∴ `(PN)/(NR) = (PM)/(MQ)` …...[Basic proportionality theorem]
∴ But PM = 15, MQ = 10, NR = 8 (Given)
∴ Equation (i) becomes,
`(PN)/8 = 15/10`
PN = `(15 xx 8)/10`
= `(15 xx 4)/5`
= `3 xx 4`
∴ PN = 12 units
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